[Feb-2022 Newly Released] Pass 1z1-071 Exam - Real Questions & Answers
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What is the duration, language, and format of Oracle 1Z0-071: Oracle Database SQL Exam
- Certification Validity period : 3 years.
- Passing score: 63%
- The type of questions is Multiple Choice questions.
- This exam consists of 78 questions.
Certifications from the Oracle database include frequent recertification. To keep your certificate valid, you must upgrade to the latest version within 1 year of the revocation of Oracle’s credentials.
NEW QUESTION 137
Which three are true about system and object privileges? (Choose three.)
- A. Adding a primary key constraint to an existing table in another schema requires a system privilege
- B. Revoking a system privilege that was granted with WITH ADMIN OPTION has a cascading effect
- C. WITH GRANT OPTION cannot be used when granting an object privilege to PUBLIC
- D. WITH GRANT OPTION can be used when granting an object privilege to both users and roles
- E. Revoking an object privilege that was granted with the WITH GRANT OPTION clause has a cascading effect.
- F. Adding a foreign key constraint pointing to a table in another schema requires the REFERENCES object privilege
Answer: D,E,F
Explanation:
Explanation
Reference https://docs.oracle.com/cd/B28359_01/network.111/b28531/authorization.htm#DBSEG004
NEW QUESTION 138
Examine the structure of the MARKStable:
Which two statements would execute successfully? (Choose two.)
SELECT SUM(DISTINCT NVL(subject1,0)), MAX(subject1)
- A. FROM marks
WHERE subject1 > subject2;
SELECT student_name subject1 - B. FROM marks
WHERE student_name IS NULL;
SELECT student_name,SUM(subject1) - C. FROM marks
WHERE student_name LIKE 'R%'; - D. FROM marks
WHERE subject1 > AVG(subject1);
SELECT SUM(subject1+subject2+subject3)
Answer: A,B
NEW QUESTION 139
View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables.
There is only one customer with the cust_last_name column having value Roberts. Which INSERT statement should be used to add a row into the ORDERS table for the customer whose CUST_LAST_NAME is Roberts and CREDIT_LIMIT is 600?
- A. INSERT INTO orders (order_id, order_data, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), order_total)VALUES (1,
'10-mar-2007', 'direct', &customer_id, 1000). - B. INSERT INTO(SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_totalFROM orders o, customers cWHERE o.customer_id = c.customer_idAND c.cust_last_name='Roberts' AND c.credit_limit=600 )VALUES (1, '10-mar-2007', 'direct', (SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), 1000);
- C. INSERT INTO ordersVALUES(1, '10-mar-2007', 'direct',(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), 1000);
- D. INSERT INTO orders (order_id, order_data, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' ANDcredit_limit=600), order_total)VALUES(1,
'10-mar-2007', 'direct', &&customer_id, 1000);
Answer: C
NEW QUESTION 140
View the Exhibit and examine the structure of the ORDERS table. The ORDER_ID column is the PRIMARY KEY in the ORDERS table.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_orders(ord_id, ord_date DEFAULT SYSDATE, cus_id)
AS
SELECT order_id.order_date,customer_id
FROM orders;
Which statement is true regarding the above command?
- A. The NEW_ODRDERS table would not get created because the DEFAULT value cannot be specified in the column definition.
- B. The NEW_ODRDERS table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
- C. The NEW_ODRDERS table would get created and all the constraints defined on the specified columns in the ORDERS table would be passed to the new table.
- D. The NEW_ODRDERS table would get created and only the NOT NULL constraint defined on the specified columns would be passed to the new table.
Answer: D
NEW QUESTION 141
Which two statements are true about single-row functions? (Choose two.)
- A. MOD: returns the quotient of a division operation
- B. FLOOR: returns the smallest integer greater than or equal to a specified number
- C. CONCAT: can be used to combine any number of values
- D. CEIL: can be used for positive and negative numbers
- E. TRUNC: can be used with NUMBER and DATE values
Answer: A,E
Explanation:
Explanation/Reference: https://www.folkstalk.com/2012/01/oracle-single-row-functions-examples.html
NEW QUESTION 142
View the exhibit and examine the structure of the CUSTOMERS table.
Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)
- A. finding the number of customers, in each city, whose marital status is 'married'.
- B. listing of customers who do not have a credit limit and were born before 1980
- C. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
- D. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
- E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
Answer: C,E
NEW QUESTION 143
View the Exhibit and examine the structure of the ORDERS table.
Which UPDATE statement is valid?
- A. UPDATE ordersSET order_date = TO_DATE('12-mar-2007','dd-mon-yyyy'),SET order_total = TO_NUMBER (NULL)WHERE order_id = 2455;
- B. UPDATE ordersSET order_date = '12-mar-2007',order_total = NULLWHERE order_id
2455; - C. UPDATE ordersSET order_date = '12-mar-2007',AND order_total
TO_NUMBER(NULL)WHERE order_id = 2455; - D. UPDATE ordersSET order_date = '12-mar-2007',order_total IS NULLWHERE order_id
= 2455;
Answer: B
NEW QUESTION 144
View the Exhibit and examine the structure of the CUSTOMERS and CUST_HISTORY tables.
The CUSTOMERS table contains the current location of all currently active customers.
The CUST_HISTORY table stores historical details relating to any changes in the location of all current as well as previous customers who are no longer active with the company.
You need to find those customers who have never changed their address.
Which SET operator would you use to get the required output?
- A. UNION
- B. UNION ALL
- C. MINUS
- D. INTERSECT
Answer: C
NEW QUESTION 145
Examine these SQL statements which execute successfully:
Which two statements are true after execution? (Choose two.)
- A. The foreign key constraint will be enabled and DEFERRED.
- B. The foreign key constraint will be disabled.
- C. The primary key constraint will be enabled and IMMEDIATE.
- D. The foreign key constraint will be enabled and IMMEDIATE.
- E. The primary key constraint will be enabled and DEFERRED.
Answer: D,E
Explanation:
Explanation/Reference:
NEW QUESTION 146
View the Exhibit and examine the data in the PRODUCTS table.
You must display product names from the PRODUCTS table that belong to the 'Software/other' category with minimum prices as either $2000 or $4000 and with no unit of measure.
You issue this query:
Which statement is true?
- A. It executes successfully but returns no result.
- B. It generates an error because the condition specified for PROD_UNIT_OF_MEASURE is not valid.
- C. It generates an error because the condition specified for the PROD_CATEGORY column is not valid.
- D. It executes successfully and returns the required result.
Answer: A
NEW QUESTION 147
View the exhibit and examine the description of the PRODUCT_INFORMATION table.
Which SQL statement would retrieve from the table the number of products having LIST_PRICE as NULL?
- A. SELECT COUNT (list_price)FROM product_informationWHERE list_price is NULL
- B. SELECT COUNT (NVL(list_price, 0))FROM product_informationWHERE list_price is NULL
- C. SELECT COUNT (DISTINCT list_price)FROM product_informationWHERE list_price is NULL
- D. SELECT COUNT (list_price)FROM product_informationWHERE list_price i= NULL
Answer: B
NEW QUESTION 148
Which statement is true regarding the USINGclause in table joins? (Choose two.)
- A. It can be used to access data from tables through equijoins as well as nonequijoins.
- B. It can be used to restrict the number of columns used in a NATURALjoin.
- C. It can be used to join tables that have columns with the same name and compatible data types.
- D. It can be used to join a maximum of three tables.
Answer: B,C
NEW QUESTION 149
You need to list the employees in DEPARTMENT_ID20 days in a single row, ordered by HIRE_DATE.
Examine the sample output:
Which query will provide the required output?
SELECT LISTAGG(last_name)
- A. WITHIN GROUP ORDER BY (hire_date) "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30; SELECT LISTAGG(last_name, '; ') "Emp_list", MIN(hire_date) "Earliest"
- B. FROM employees
WHERE department_id = 30;
WITHIN GROUP ORDER BY (hire_date);
SELECT LISTAGG(last_name, '; ') "Emp_list", MIN(hire_date) "Earliest" - C. FROM employees
WHERE department_id = 30;
ORDER BY (hire_date); - D. WITHIN GROUP ORDER BY (hire_date) "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30; SELECT LISTAGG(last_name, '; ')
Answer: A
NEW QUESTION 150
View the Exhibit and examine the data in the employees table.
You want to generate a report showing the total compensation paid to each employee to date.
You issue the following query:
What is the outcome?
- A. It executes successfully and gives the correct output.
- B. It generates an error because the usage of the round function in the expression is not valid
- C. It executes successfully but does not give the correct output.
- D. It generates an error because the alias is not valid.
- E. It generates an error because the concatenation operator can be used to combine only two items.
Answer: C
NEW QUESTION 151
Which two statements are true regarding the EXISTS operator used in the correlated subqueries? (Choose two.)
- A. It is used to test whether the values retrieved by the outer query exist in the result set of the inner query.
- B. The outer query continues evaluating the result set of the inner query until all the values in the result set are processed.
- C. It is used to test whether the values retrieved by the inner query exist in the result of the outer query.
- D. The outer query stops evaluating the result set of the inner query when the first value is found.
Answer: A,D
NEW QUESTION 152
Evaluate the following SQL commands:
The command to create a table fails. Identify the reason for the SQL statement failure.
- A. You cannot use ORD_NOand ITEM_NOcolumns as a composite primary key because ORD_NOis also the FOREIGN KEY.
- B. You cannot use SYSDATEin the condition of a CHECKconstraint.
- C. You cannot use the NEXTVALsequence value as a DEFAULTvalue for a column.
- D. You cannot use the BETWEENclause in the condition of a CHECKconstraint.
Answer: B
NEW QUESTION 153
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Exam Details
The Oracle 1Z0-071 exam is made up of 78 multiple-choice questions that are to be completed within the allocated timeframe of 120 minutes. The test is proctored by Pearson VUE, the official partner of Oracle. To schedule your session, you need to pay the fee of $245. But before that, you have to create an account with CertView, a web-based portal for all the Oracle certification activity. After you complete the exam, you will receive a notification from Oracle to your email address that your results are available on CertView. Log into the portal and click “See My New Exam Result Now” to find out whether you passed your 1Z0-071 test or not. To ace this exam, you need to give no less than 63% of correct answers.
It is strongly recommended that you undertake the relevant training before attempting the certification test. You can opt for one of the official courses offered by Oracle on its website. The examinees are encouraged to use Oracle training in combo with hands-on experience gained with the help of practical labs.
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